taking off the http or https off a javascript string

Question

I have the following strings

http://example.com
https://example.com
http://www.example.com

how do i get rid of the http:// or

Answer 1

This answer extends some answers above, http://, https://, or // which is also common.

Thanks for answers above that led me to this!

const urls = [ "http://example.com", "https://example.com", "//example.com" ]

// the regex below states: replace `//` or replace `//` and the 'stuff'
const resolveHostNames = urls.map(url => url.replace(/\/\/|.+\/\//, ''))

console.log(resolveHostNames);

Here's a link to a codepen.

Answer 2

Javascript use of split function also dervies the solution. Awesome !!!

var url = "https://example.com";

url = url.split("://")[1];    // for https use url..split("://")[0];
console.log(url);

Answer 3

var str = "https://site.com";

str = str.substr( str.indexOf(':') + 3 );

Instead of .substr(), you could also use .slice() or .substring(). They'll all produce the same result in this situation.

str = str.slice( str.indexOf(':') + 3 );

str = str.substring( str.indexOf(':') + 3 );

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EDIT: It appears as though the requirements of the question have changed in a comment under another answer.

If there possibly isn't a http:// in the string, then do this:

var str = "site.com";

var index = str.indexOf('://');
if( index > -1 )
   str = str.substr( index + 3 );

Answer 4

var txt="https://site.com";
txt=/^http(s)?:\/\/(.+)$/i.exec(txt);
txt=txt[2];

for parsing links without http/https use this:

var txt="https://site.com";
txt=/^(http(s)?:\/\/)?(.+)$/i.exec(txt);
txt=txt[3];

Answer 5

Assuming there are no double slashes other than the protocol, you could do:

 var url = "https://example.com";
 var noProtocol = url.split('//')[1];

Answer 6

You can use the URL object like this:

const urlWithoutProtocol = new URL(url).host;