Is there a filter for divide for Django Template?

Question

I noticed there is built-in add filter, but I wasn\'t able to find divide.

I am new to Django and not sure if there is a such filter.

Answer 1

Using a custom filter:

register = template.Library()

@register.filter
def divide(value, arg):
    try:
        return int(value) / int(arg)
    except (ValueError, ZeroDivisionError):
        return None

Answer 2

Check out http://djangosnippets.org/snippets/2424/

Hope that helps you out.

Answer 3

I would use a custom template, but if you don't want to you can use the widthratio built in tag,

{% widthratio request.session.get_expiry_age 3600 1 %} 

Another example

{% widthratio value 1150000 100 %}

Syntax:

{% widthratio parm1 parm2 parm3 %}

So basically its used for scaling images, but you can use it for division. What it does is: parm1/parm2 * parm3.

Hope this helps, more on widthratio here.

Answer 4

You can use divisibleby

Returns True if the value is divisible by the argument.

For example:

{{ value|divisibleby:"3" }}

If value is 21, the output would be True.

You can see django docs

Answer 5

There is a Python module to do math operations in your templates: Django-Mathfilters.

It contains add as you said, but also div to divide:

 8 / 3 = {{ 8|div:3 }}

Answer 6

There is not it. But if you are a little hacker....

http://slacy.com/blog/2010/07/using-djangos-widthratio-template-tag-for-multiplication-division/

to compute A*B: {% widthratio A 1 B %}

to compute A/B: {% widthratio A B 1 %}

to compute A^2: {% widthratio A 1 A %}

to compute (A+B)^2: {% widthratio A|add:B 1 A|add:B %}

to compute (A+B) * (C+D): {% widthratio A|add:B 1 C|add:D %}

Also you can create a filter to division in 2 minutes