load a php image using src

Question

Is it possible to load a image using:

?

for image.php:

$ima         


        

Answer 1

You have to change the header content-type and print the contents of the image file. Here is an example for your image.php file:

$image_id = $_GET['image_id']; 
$filename = "image".$image_id.".png"; 
header('Content-Type: image/png');
print file_get_contents($filename);

Answer 2

one liner....

echo (file_exists($_GET['image_id'])) ? header("Content-Type:image/png").readfile($_GET['image_id']).die() : false;

Answer 3

Is it possible to load a image use: <img src="image.php?image_id=1">

Yes. URLs are URLs. It is content-type that determines content, not any characters in the URL itself.

$image_id = $_GET['image_id']; echo "image".$image_id.".png";

Not like that. You either have to read the image file in and then output it with a suitable content-type, or redirect (with a location header) to a static image.

Answer 4

No, this is not possible that way. You would have to write the contents of the image file to the output stream instead.

Answer 5

If you have the png contents in the database, follow the other answers. If all you need is the id from the database, simply <img src="image<?=$image_id?>.png">

Answer 6

you must return a valid image, use file_get_contents or readfile for get the conent of image then output to browser

 header("Content-Type:image/png");

    $image_id = $_GET['image_id']; 

    if(is_file($file = "image".$image_id.".png") ||  is_file($file = "no_image.png"))
        readfile($file);