I\'m working on my project and I want to overload operator <<
which should print out my object on console.
Object is called \"config\" and in its temp
Here's one way to solve the problem.
Declare the operator<<
function first, before config
is defined. In order to declare the function, you have to forward declare the class template.
template <typename T> class config;
template <typename T> std::ostream& operator<<(std::ostream &out,
const config<T> &c);
In the class, make the function a friend by using T
as the template parameter.
friend ostream& operator<< <T>(ostream &out, const config &c);
// Notice this ^^^^
// This makes sure that operator<< <int> is not a friend of
// config<double>. Only operator<< <double> is a friend of
// config<double>
Here's a working program with those changes:
#include <string>
#include <iostream>
template <typename T> class config;
template <typename T> std::ostream& operator<<(std::ostream &out,
const config<T> &c);
template <typename T> class config
{
T *attribute1, *attribute2, *attribute3, *attribute4;
std::string attribName1, attribName2, attribName3, attribName4;
public:
config(void)
{
attribute1 = new T[3];
attribute2 = new T[3];
attribute3 = new T[3];
attribute4 = new T[3];
}
~config(void)//destructor
{
delete [] attribute1;
delete [] attribute2;
delete [] attribute3;
delete [] attribute4;
}
//operator
friend std::ostream& operator<< <T>(std::ostream &out,
const config &c);
};
template <typename T> std::ostream& operator<<(std::ostream &out,
const config<T> &c)
{
for(int i=0;i<3;i++)
{
out << c.attribute1[i] << " "
<< c.attribute2[i] << " "
<< c.attribute3[i] << " "
<< c.attribute2[i] << std::endl;
}
return out;
}
int main()
{
config<double> x;
std::cout << x << std::endl;
}
Output:
0 0 0 0 0 0 0 0 0 0 0 0