convert xml to jsonx using xslt

后端 未结 1 673
长发绾君心
长发绾君心 2020-12-20 04:11

Can anyone help me out in getting the below with an array..I have to generate the generalised xsl.. Input XML:


    
        

        
相关标签:
1条回答
  • 2020-12-20 04:37

    More generalized solution. Requires XSLT 2.0

    <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:json="http://www.ibm.com/xmlns/prod/2009/jsonx" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
        <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" />
    
        <xsl:template match="/">
            <xsl:element name="json:object">
                <xsl:apply-templates />    
            </xsl:element>
        </xsl:template>
    
        <xsl:template match="*[*]">
            <xsl:param name="nodeName" select="name()" />
            <xsl:variable name="firstNodeName" select="name(*[1])" />
    
            <xsl:element name="json:object">
                <xsl:if test="$nodeName">
                    <xsl:attribute name="name" select="$nodeName" />
                </xsl:if>
                <xsl:choose>
                    <xsl:when test="(count(*) > 1) and (every $x in */name() satisfies $x=$firstNodeName)">
                        <xsl:element name="json:array">
                            <xsl:attribute name="name" select="$firstNodeName" />
    
                            <xsl:apply-templates >
                                <xsl:with-param name="nodeName" select="''" />
                            </xsl:apply-templates>
                        </xsl:element>
                    </xsl:when>
                    <xsl:otherwise>
                        <xsl:apply-templates />
                    </xsl:otherwise>
                </xsl:choose>
            </xsl:element>
        </xsl:template>
    
        <xsl:template match="*[not(*)]">
            <xsl:element name="json:string">
                <xsl:attribute name="name">
                    <xsl:value-of select="name()" />
                </xsl:attribute>
                <xsl:value-of select="text()" />
            </xsl:element>
        </xsl:template> 
    </xsl:stylesheet>
    

    Applied to the provided sample XML, produces following output:

    <?xml version="1.0" encoding="UTF-8"?>
    <json:object xmlns:json="http://www.ibm.com/xmlns/prod/2009/jsonx">
        <json:object name="Login">
            <json:object name="Groups">
                <json:array name="Group">
                    <json:object>
                        <json:string name="Name">john</json:string>
                        <json:string name="Password"></json:string>
                    </json:object>
                    <json:object>
                        <json:string name="Name">john</json:string>
                        <json:string name="Password"></json:string>
                    </json:object>
                </json:array>
            </json:object>
        </json:object>
    </json:object>
    

    The above solution was tested on this site: http://xslttest.appspot.com/

    EDIT:

    every $x in */name() satisfies $x=$firstNodeName is XPATH 2.0 construction that checks if all the elements in */name() sequence are equal to $firstNodeName. So this whole condition actually means checking if a node has more than one child with the same name - this is a condition for checking if we're dealing with json:array case.

    0 讨论(0)
提交回复
热议问题