C++ Compare and replace last character of stringstream

Question

I would like to check the following:

1. If the last character appended to the stringstream is a comma.
2. If it is remove it.

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Answer 1

The way I often deal with these loops where you want to put something like a space or a comma between a list of items is like this:

int main()
{
    // initially the separator is empty
    auto sep = "";

    for(int i = 0; i < 5; ++i)
    {
        std::cout << sep << i;
        sep = ", "; // make the separator a comma after first item
    }
}

Output:

0, 1, 2, 3, 4

If you want to make it more speed efficient you can output the first item using an if() before entering the loop to output the rest of the items like this:

int main()
{
    int n;

    std::cin >> n;

    int i = 0;

    if(i < n) // check for no output
        std::cout << i;

    for(++i; i < n; ++i) // rest of the output (if any)
        std::cout << ", " << i; // separate these
}

In your situation the first solution could work like this:

    std::regex tok_pat("[^\\[\\\",\\]]+");
    std::sregex_token_iterator tok_it(command.begin(), command.end(), tok_pat);
    std::sregex_token_iterator tok_end;
    std::string baseStr = tok_end == ++tok_it ? "" : std::string(*tok_it);

    auto sep = ""; // empty separator for first item

    while (baseStr == "OVER")
    {
        // extract command parameters
        str << sep << "extracted_parameters";
        sep = ","; // make it a comma after first item
    }

And the second (possibly more time efficient) solution:

    std::regex tok_pat("[^\\[\\\",\\]]+");
    std::sregex_token_iterator tok_it(command.begin(), command.end(), tok_pat);
    std::sregex_token_iterator tok_end;
    std::string baseStr = tok_end == ++tok_it ? "" : std::string(*tok_it);

    if (baseStr == "OVER")
    {
        // extract command parameters
        str << "extracted_parameters";
    }

    while (baseStr == "OVER")
    {
        // extract command parameters
        str << "," << "extracted_parameters"; // add a comma after first item
    }