How to iterate between 0.1f and 1.0f with 0.1f increments in Java? [duplicate]

Answer 1

for(float i =1.0f;i<10f;i+=1f)
System.out.println(i/10f);`

is ugly as hell but works here (Ubuntu AMD64 OpenJDK)

Answer 2

floats are binary, and don't represent decimals well

if applicable Iterate in 1/8ths or 0.125 instead.

Answer 3

You could try this:

for(int i = 1; i < 10; i++)
    System.out.println(i/10f);

0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9

What you are seeing is a product of inaccuracies that are intrinsic to floats, which naturally build up if you add them continuously, as you do in the code you posted. If we use ints in the loop instead, we avoid the float-addition and, therefore, also the error build-up.

Answer 4

Use integers in your for loop to avoid repeated floating point math, which compounds floating-point errors.

for (int i = 1; i < 10; i++)
{
   float f = (float) i / 10.0f;
   System.err.println(f);
}