This is my code:
Microsoft.CSharp.CSharpCodeProvider provider = new CSharpCodeProvider();
ICodeCompiler compiler = provider.CreateCompiler();
CompilerParamet
You could use the OutputAssembly
property of CompilerParameters
to sets the name (path) of the output assembly.
From your example:
...
CompilerParameters compilerparams = new CompilerParameters();
compilerparams.GenerateInMemory = false;
compilerparams.OutputAssembly = "OutputAssembly.dll";
CompilerResults results = compiler.CompileAssemblyFromSource(compilerparams, code);
...
With OutputAssembly property you can specify just the assembly name. The Assembly will be created in current directory. If you need to specify the full path you have to set the compiler options string in this way:
System.CodeDom.Compiler.CompilerParameters parameters = new CompilerParameters();
parameters.GenerateExecutable = false;
parameters.CompilerOptions = " /out:C:\\Temp\\" + outputAssemblyFile;
Look here, many options can be set in this property. If you set CompilerOptions then OutputAssembly property will be ignored.
I hope this can help.