SQL Query with MySQL

Question

I am implementing a Restful Web Service in java (JAX-RS) using Jesey. I run it on Tomcat v7.0 I use Hibernate to map the data to the database (MySQL). I have a query to fetc

Answer 1

mysql doesn't have TOP, use the ORDER BY and LIMIT clauses at the end of the sql.

Answer 2

I am not sure TOP function is available in mysql but try to use it and share the result. you can write like this: SELECT TOP 2 * FROM Persons

check this link, it will furnish you with more details. enter link description here

Answer 3

I think you are asking for the top 3 Deliverables from Task ordered by ID. You could try something like this:

Edit: Ok I'll take one more stab at this. This should give you the top 3 Deliverables ordered by Task.id taking only the Deliverable associated to the max(Task.id)

deliverables = 
        (List<Deliverable>) session.createQuery(
            "from Deliverable as d, Task as t
                where t.deliverable.id = d.id and
                t.id = (select max(t1.id) from Task t1 where t1.deliverable.id = d.id)
                and d.project.id= :id
                and t.user.username = :name
                order by t.id desc")
        .setMaxResults(3)
        .setLong("id", projectId)
        .setString("name", username)
        .list();