why does a char + another char = a weird number

Question

Here\'s the code snippet:

public static void main (String[]arg) 
{
    char ca = \'a\' ; 
    char cb = \'b\' ; 
    System.out.println (ca + cb) ; 
}


        

Answer 1

I don't speak Java, but 195 is 97 + 98 = the ASCII codes for a and b. So obviously, ca and cb are interpreted as their integer values, probably because of the + addition which does not seem to lead to a string concatenation automatically.

Answer 2

If you want to have a String as result of the + operator you have to use type String as operands.

You should write:

public static void main (String[]arg) 
{
    String ca = "a" ; 
    String cb = "b" ; 
    System.out.println (ca + cb) ; 
}

The + operator applied on char operands behaves as the arithmetic sum.

Answer 3

+ of two char is arithmetic addition, not string concatenation. You have to do something like "" + ca + cb, or use String.valueOf and Character.toString methods to ensure that at least one of the operands of + is a String for the operator to be string concatenation.

JLS 15.18 Additive Operators

If the type of either operand of a + operator is String, then the operation is string concatenation.

Otherwise, the type of each of the operands of the + operator must be a type that is convertible to a primitive numeric type, or a compile-time error occurs.

As to why you're getting 195, it's because in ASCII, 'a' = 97 and 'b' = 98, and 97 + 98 = 195.

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This performs basic int and char casting.

 char ch = 'a';
 int i = (int) ch;   
 System.out.println(i);   // prints "97"
 ch = (char) 99;
 System.out.println(ch);  // prints "c"

This ignores the issue of character encoding schemes (which a beginner should not worry about... yet!).

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As a note, Josh Bloch noted that it is rather unfortunate that + is overloaded for both string concatenation and integer addition ("It may have been a mistake to overload the + operator for string concatenation." -- Java Puzzlers, Puzzle 11: The Last Laugh). A lot of this kinds of confusion could've been easily avoided by having a different token for string concatenation.

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See also

• Is concatenating with an empty string to do a string conversion really that bad?

Answer 4

The + operator doesn't operate over characters like it does over strings. What's happening here is that a and b are being cast to their integer ASCII codepoints - 97 and 98 - and then added together.