What to do with php after jquery .serialize()

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慢半拍i
慢半拍i 2020-12-19 19:37

Ok somehow im having the hardest time figuring this out so i want to do an call ajax with a form and im using jquery to serialize it with .serialize(). The data being sent t

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  • 2020-12-19 19:54

    Try to use json in jQuery and json_decode in php then.

    • http://api.jquery.com/serializeArray/
    • http://code.google.com/p/jquery-json/
    • http://php.net/manual/function.json-decode.php
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  • 2020-12-19 19:54

    You values exists in formInfo index of $_POST array,

    print_r( $_POST['formInfo'] );
    
    echo $_POST['formInfo']['key1'];
    
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  • 2020-12-19 20:00

    If you're submitting the form data with jQuery's Ajax functionality, there should not be a problem with using .serialize(). The server should see and urldecode automatically the POST content.

    As a demonstration, see this code:

    HTML

    <form id="category-dynamic" class="dynamic">
       <fieldset id="inner-fieldset">
          <legend id="new-category">
            <label for="category-name">Category Name: </label>
            <input type="text" name="category-name" value="" />
          </legend>
          <ul id="category-fields">
             <li>
               <label>Field #1:</label><br />
               <input type="text" name="fields[]" value="" />
             </li>
             <li>
               <label>Field #2:</label><br />
               <input type="text" name="fields[]" value="" />
             </li>
          </ul>
       </fieldset>
    </form>
    <h3>POST Result</h3>
    <pre></pre>
    

    jQuery

    $(document).ready(function(){
        $('pre').html($('#category-dynamic').serialize());
    
        $.post("http://jfcoder.com/test/processor.php", $('#category-dynamic').serialize(), function(data){
             $('pre').html($('pre').html()+"\n\n"+data);
        });
    });
    

    EDIT

    And the processor.php file contents:

    <?php
    print_r($_POST);
    ?>
    

    EDIT 2

    I think your error is that you're sending the content in such a way as to make the form data be a text string instead of url-encoded content.

    For instance, you could do this:

    var formSubmit = $(this).serialize() + "&formSubmit=true";
    $.post('ajax.php', formSubmit);
    

    And you'd have the same effect, and the server would be able to expand your POST variables without incident.

    EDIT 3

    See this example:

    Where the code is:

    $(document).ready(function(){
        var serial = $('#category-dynamic').serialize() + "&formSubmit=true";
        $('pre').html(serial);
        $.post("http://jfcoder.com/test/processor.php", serial, function(data){
             $('pre').html($('pre').html()+"\n\n"+data);
        });
    });
    

    Note the addition of the "&formSubmit=true" to the serial data. This outputs from the PHP page:

    POST Result
    
    category-name=&fields%5B%5D=&fields%5B%5D=&formSubmit=true
    
    Array
    (
        [category-name] => 
        [fields] => Array
            (
                [0] => 
                [1] => 
            )
    
        [formSubmit] => true
    )
    

    EDIT 4

    This uses the method you describe. See the difference?

    $(document).ready(function(){
        var serial = $('#category-dynamic').serialize();
        $('pre').html(serial);
        $.post("http://jfcoder.com/test/processor.php", {"formSubmit":"true","serial":serial}, function(data){
             $('pre').html($('pre').html()+"\n\n"+data);
        });
    });
    

    OUTPUT

    POST Result
    
    category-name=&fields%5B%5D=&fields%5B%5D=
    
    Array
    (
        [formSubmit] => true
        [serial] => category-name=&fields%5B%5D=&fields%5B%5D=
    )
    
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