Python: TypeError: takes exactly 1 argument (2 given)

Question

I\'m currently using singpath.com to practice my python, but I face an issue with a problem:

The expected result is:

>>>CurryPuff(3) 
3.60 
         


        

Answer 1

You can't call a function with 1 argument if it expects 2, as CurryPuff() does. However, you can define a default argument that is used if no argument is passed:

def CurryPuff(x, typePuff=None):
    if typePuff is None:
       # and so on...

You can do this with any value for any argument. You may only omit arguments if a default value is defined.