Any more concise way to set default values?

Question

Since PHP 5.3, it is possible to leave out the middle part of the ternary operator. Expression expr1 ?: expr3 returns expr1 if expr1 evaluates to TRUE, an

Answer 1

Here is a shorter syntax:

isset($v) || $v="default value";

Answer 2

TL;DR - No, that expression can't be made any shorter.

What you want is for the shortened ternary expression to perform an implicit isset(). This has been discussed on the mailing list and an ifsetor RFC has been created that covers the concept as well.

Since the shortened ternary operator already existed at the time of the above discussion, something like this was proposed using a non-existent operator ??:

// PROPOSAL ONLY, DOES NOT WORK
$v = $v ?? 'default value';

Assign 'default value' if $v is undefined.

However, nothing like this has been implemented in the main language to date. Until then, what you have written can't be made any shorter.

This horrible construct is shorter, but note that it's not the same because it assigns the default value if the variable exists but evaluates to false:

// DO NOT USE
$v = @$v ?: 'default value';

Answer 3

Just asked this and was pointed here. So in case you use a key of an array, this might be an improvement

function isset_get($array, $key, $default = null) {
    return isset($array[$key]) ? $array[$key] : $default;
}

Answer 4

Nope. That's the right way if you don't really know whether $v is set.

Answer 5

No way.If you use ternary operator.