REGEX-String and escaped quote

Question

How to get what is between the quotes in the following two texts ?

text_1 = r\"\"\" \"Some text on \\\"two\\\" lines with a backslash escaped\\\\\" \\
     +         


        

Answer 1

>>> import re
>>> text_1 = r""" "Some text on \"two\" lines with a backslash escaped\\" \
     + "Another text on \"three\" lines" """
>>> text_2 = r""" "Some text on \"two\" lines with a backslash escaped\\" + "Another text on \"three\" lines" """
>>> re.findall(r'\\"([^"]+)\\"', text_2)
['two', 'three']
>>> re.findall(r'\\"([^"]+)\\"', text_1)
['two', 'three']

Perhaps you want this:

re.findall(r'\\"((?:(?<!\\)[^"])+)\\"', text)

Answer 2

>>> import re
>>> text = "Some text on\n\"two\"lines" + "Another texton\n\"three\"\nlines"
>>> re.findall(r'"(.*)"', text)
["two", "three"]

Answer 3

Match everything but a double quote:

import re
text = "Some text on \"two\" lines" + "Another text on \"three\" lines"
print re.findall(r'"([^"]*)"', text)

Output

['two', 'three']

Answer 4

"(?:\\.|[^"\\])*"

matches a quoted string, including any escaped characters that occur within it.

Explanation:

"       # Match a quote.
(?:     # Either match...
 \\.    # an escaped character
|       # or
 [^"\\] # any character except quote or backslash.
)*      # Repeat any number of times.
"       # Match another quote.