Why quote it at all? I can't imagine the Google API requires (or even expects) that value to be quoted.
$json_url = file_get_contents('http://maps.google.com/maps/api/geocode/json?address=jaipur&sensor=false'); //line 9
Or, is jaipur
a variable? If so:
$json_url = file_get_contents("http://maps.google.com/maps/api/geocode/json?address=$jaipur&sensor=false"); //line 9
Hard to tell from your question what it is you're trying to accomplish...
You have to use your escape characters correctly. You can't have a single-quote ('
) inside of a single-quote-encapsulated string. It breaks it. In order to continue the string and have PHP interpret your inner single-quote literally, you have to escape it with \
.
$json_url = file_get_contents('http://maps.google.com/maps/api/geocode/json?address=\'jaipur\'&sensor=false');
Or you can use the alternative string encapsulator, double-quote ("
).
$json_url = file_get_contents("http://maps.google.com/maps/api/geocode/json?address='jaipur'&sensor=false");
For future reference, Parse error: syntax error, unexpected T_STRING
usually means you have a bad string somewhere on that line.
$json_url = file_get_contents("http://maps.google.com/maps/api/geocode/json?address='jaipur'&sensor=false");
Or escaping it with \