It\'s quite straight forward in java to parse number from String, i.e. with Integer.parseInt(s) if string in the format \'n\' or \'-n\', but unfortunately
Just FYI, this has been fixed in Java 7.
from, Java SE8 for the Really Impatient
Prior to
JDK 1.7
, what was the result of the following code segment?
double x = Double.parseDouble("+1.0");
int n = Integer.parseInt("+1");
Pat yourself on the back if you knew the answer:
+1.0
has always been a valid floating-point number, but until Java 7,+1
was not a valid integer. This has now been fixed for all the various methods that constructint
,long
,short
,byte
, andBigInteger
values from strings. There are more of them than you may think. In addition to parse (Int|Long|Short|Byte), there are decode methods that work with hexadecimal and octal inputs, andvalueOf
methods that yield wrapper objects. TheBigInteger(String)
constructor is also updated.
Integer.parseInt(s.replace("+", ""));
In truth there are many gotchas using Integer to parse numbers like that, in that Integer has very specific bounds of size and format ("1,000,000.00") isn't parsing that way, but I'm taking your question as Integer.parseInt meets your needs just fine, you just have to deal with a + in your data.