Using Python to open a shell environment, run a command and exit environment

Question

I\'m trying to automate a process using python. If I am just in the terminal the workflow looks like:

user:> . /path/to/env1.sh
user:> python somethin         


        

Answer 1

subprocess calls (particular Popen) accepts an env argument which is a mapping of environement variables to values. You can use that. e.g.

env = {'FOO': 'Bar', 'HOME': '/path/to/home'}
process = subprocess.Popen(['python', 'something.py'], env=env)

Of course, usually, it's better to just call some functions after *import*ing something.py instead of spawning a whole new process.

Answer 2

Here is a help for you.... For running command you could do:

1)

from subprocess import call
call(["ls", "-l"])

2)

import os
os.system("command")

Example:

import os
f = os.popen('date')
now = f.read()
print "Today is ", now

For enabling terminal you can import os module:

import os
os.system('python script.py')

Or as mentioned you can use import subprocess

Answer 3

You can use subprocess:

>>> import subprocess
>>> subprocess.call('python something.py', shell = True)

Or you can use os:

>>> import os
>>> os.system('python something.py')

Here is an example (turn on your speakers):

>>> import os
>>> os.system('say Hello')

Answer 4

p = subprocess.Popen(". /path/to/env.sh", shell = True, stdout=subprocess.PIPE).communicate()
subprocess.call("python something.py", shell = True).communicate()

Answer 5

As I understand you want to run a command and then pass it other commands:

from subprocess import Popen, PIPE

p = Popen("/path/to/env.sh", stdin=PIPE)   # set environment, start new shell
p.communicate("python something.py\nexit") # pass commands to the opened shell