PHP: file_get_contents('php://input') returning string for JSON message

Question

I am trying to read in a JSON message in my PHP app and this is my php code:

$json = file_get_contents(\'php://input\');
$obj = json_decode($json, TRUE);
ech         


        

Answer 1

If you are using javascript to send JSON, to a php file

send_recieve.js

var myObject = JSON.stringify({"name":"John","age":30,"city":"New York"});
var xhr = new XMLHttpRequest();
xhr.open("POST","http://localhost/dashboard/iwplab/j-comp/receive_send.php",false);
xhr.setRequestHeader("Content-type","application/json");
xhr.onreadystatechange = function(){
    if(xhr.readyState==4){console.log("xhr response:"+xhr.response)}
    alert(xhr.responseText);
 };
 xhr.send(myObject);

recieve_send.php

<?php
    $var = json_decode(file_get_contents("php://input"),true);
    echo "Data recieved by PHP file.\n";
    if ($var["name"]=="John"){
        echo "a";
    }
    else{
        echo "b";
    }
    //Manipulate/validate/store/retrieve to database here
    //echo statements work as response
    echo "\nSent";

?>

echo statements work as a response.

Answer 2

The problem may be form php://input (is a read-only stream that allows you to read raw data from the request body). change some setting from php.ini , try to make "allow_url_fopen" on.

Answer 3

there are two type for executing this type of request

First : you can use it as an stdClassObject for this

$data = json_decode(file_get_contents('php://input'));

it will return a object and you can retrieve data from this like

$name = $data->name;

Second : you can use it as an array for this

$data = json_decode(file_get_contents('php://input'), true);

it will return a object and you can retrieve data from this like

$name = $data['name'];

Answer 4

Your use of json_decode is creating an associative array, not an object. You can treat it like an array, instead of an object. If you want an object, use this, instead:

$obj = json_decode($json);

See the documentation on the second parameter to json_decode():

assoc When TRUE, returned objects will be converted into associative arrays.

Also, as Johannes H. pointed out in the comments, the output of echo $json; indicates that you are not actually receiving JSON, in the first place, so you will need to address that, as well. You asked why it isn't JSON; without seeing how you are requesting this script, it's impossible to say for sure.

Answer 5

Use this one result will

$chd = json_decode(file_get_contents('php://input'), TRUE);
$childs = implode("",$chd);

Answer 6

$obj = json_decode($json);

Just remove the true