How to use ORDER BY inside UNION

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离开以前 2020-12-19 03:36

I want to use ORDER BY on every UNION ALL queries, but I can\'t figure out the right syntax. This is what I want:

(
SELECT id, user_id, other_id, name 
FROM          


        
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  • 2020-12-19 03:53

    Don't use ORDER BY in an individual SELECT statement inside a UNION, unless you're using LIMIT with it.

    The MySQL docs on UNION explain why (emphasis mine):

    To apply ORDER BY or LIMIT to an individual SELECT, place the clause inside the parentheses that enclose the SELECT:

    (SELECT a FROM t1 WHERE a=10 AND B=1 ORDER BY a LIMIT 10) UNION
    (SELECT a FROM t2 WHERE a=11 AND B=2 ORDER BY a LIMIT 10);
    

    However, use of ORDER BY for individual SELECT statements implies nothing about the order in which the rows appear in the final result because UNION by default produces an unordered set of rows. Therefore, the use of ORDER BY in this context is typically in conjunction with LIMIT, so that it is used to determine the subset of the selected rows to retrieve for the SELECT, even though it does not necessarily affect the order of those rows in the final UNION result. If ORDER BY appears without LIMIT in a SELECT, it is optimized away because it will have no effect anyway.

    To use an ORDER BY or LIMIT clause to sort or limit the entire UNION result, parenthesize the individual SELECT statements and place the ORDER BY or LIMIT after the last one. The following example uses both clauses:

    (SELECT a FROM t1 WHERE a=10 AND B=1)
    UNION
    (SELECT a FROM t2 WHERE a=11 AND B=2)
    ORDER BY a LIMIT 10;
    

    It seems like an ORDER BY clause like the following will get you what you want:

    ORDER BY user_id, name
    
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  • 2020-12-19 03:57

    You just use one ORDER BY at the very end.

    The Union turns two selects into one logical select. The order-by applies to the entire set, not to each part.

    Don't use any parens either. Just:

    SELECT 1 as Origin, blah blah FROM foo WHERE x
    UNION ALL
    SELECT 2 as Origin, blah blah FROM foo WHERE y
    ORDER BY Origin, z
    
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  • 2020-12-19 04:03

    Something like this should work in MySQL:

    SELECT a.*
      FROM ( 
             SELECT ...  FROM ... ORDER BY ... 
           ) a
     UNION ALL 
    SELECT b.*
      FROM ( 
             SELECT ...  FROM ... ORDER BY ... 
           ) b
    

    Note however, absent an ORDER BY (or GROUP BY) clause on the outermost query, the order that the rows are returned is NOT guaranteed.

    If you need the rows returned in a particular sequence, you should include an ORDER BY on the outermost query. In a lot of use cases, we can just use an ORDER BY on the outermost query to satisfy the results.

    However, if you have a use case where you need all the rows from the first query returned before all the rows from the second query, one option is to include an extra discriminator column in each of the queries. For example, add ,'a' AS src in the first query, ,'b' AS src to the second query.

    Then the outermost query could include ORDER BY src, name, to guarantee the sequence of the results.


    FOLLOWUP

    In your original query, the ORDER BY in your queries is discarded by the optimizer; since there is no ORDER BY applied to the outer query, MySQL is free to return the rows in whatever order it wants.

    The "trick" in query in my answer (above) is dependent on behavior that may be specific to some versions of MySQL.

    Test case:

    populate tables

    CREATE TABLE foo2 (id INT PRIMARY KEY, role VARCHAR(20)) ENGINE=InnoDB;
    CREATE TABLE foo3 (id INT PRIMARY KEY, role VARCHAR(20)) ENGINE=InnoDB;
    
    INSERT INTO foo2 (id, role) VALUES 
      (1,'sam'),(2,'frodo'),(3,'aragorn'),(4,'pippin'),(5,'gandalf');
    INSERT INTO foo3 (id, role) VALUES 
      (1,'gimli'),(2,'boromir'),(3,'elron'),(4,'merry'),(5,'legolas');
    

    query

    SELECT a.*
      FROM ( SELECT s.id, s.role
               FROM foo2 s
              ORDER BY s.role
           ) a
     UNION ALL
    SELECT b.*
      FROM ( SELECT t.id, t.role
               FROM foo3 t
              ORDER BY t.role
           ) b
    

    resultset returned

        id  role     
     ------  ---------
          3  aragorn  
          2  frodo    
          5  gandalf  
          4  pippin   
          1  sam      
          2  boromir  
          3  elron    
          1  gimli    
          5  legolas  
          4  merry    
    

    The rows from foo2 are returned "in order", followed by the rows from foo3, again, "in order".

    Note (again) that this behavior is NOT guaranteed. (The behavior we observer is a side effect of how MySQL processes inline views (derived tables). This behavior may be different in versions after 5.5.)

    If you need the rows returned in a particular order, then specify an ORDER BY clause for the outermost query. And that ordering will apply to the entire resultset.

    As I mentioned earlier, if I needed the rows from the first query first, followed by the second query, I would include a "discriminator" column in each query, and then include the "discriminator" column in the ORDER BY clause. I would also do away with the inline views, and do something like this:

    SELECT s.id, s.role, 's' AS src
      FROM foo2 s
     UNION ALL
    SELECT t.id, t.role, 't' AS src
      FROM foo3 t
     ORDER BY src, role
    
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  • 2020-12-19 04:05
          (SELECT id, user_id, other_id, name
             FROM tablename
            WHERE user_id = 123
              AND user_in IN (...))
    UNION ALL
          (SELECT id, user_id, other_id, name
             FROM tablename
            WHERE user_id = 456
              AND user_id NOT IN (...)))
     ORDER BY name
    

    You can also simplify this query:

    SELECT id, user_id, other_id, name
      FROM tablename
     WHERE (user_id = 123 AND user_in IN (...))
        OR (user_id = 456 AND user_id NOT IN (...))
    
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