Makefile run processes in background

Question

I have this in my Makefile:

run:
     for x in *.bin ; do ./$$x ; done

such that it launches all executables one by one. I want to do this:

Answer 1

Try to execute via a subshell:

run:
     for x in *.bin ; do (./$$x &); done

Maybe make -j is a better option. Try a Makefile that looks something like this:

BINS = $(shell echo *.bin)

.PHONY: $(BINS)
run: $(BINS)

*.bin:
    ./$@

And then execute with make -j <jobs> where <jobs> is number of simultaneous jobs to run.

Answer 2

The syntax error you're getting is a shell syntax error, rather than a problem with make syntax. The ampersand is in fact a command terminator/separator, just as semicolon is; so the way to express the for loop you want is:

run:
        for x in *.bin ; do ./$$x & done

However, as others have noted, where it's practical it's usually more flexible to express things directly as make dependencies rather than complicated shell snippets and shell loops.

Answer 3

Try:

run:
    for x in *.bin ; do (./$$x &) ; done

The ()'s run the command in a subshell.