Why is KeyboardInterrupt not working in python?

Question

Why doesn\'t code like the following catch CTRL-C?

MAXVAL = 10000
STEP_INTERVAL = 10

for i in range(1, MAXVAL, STEP_INTERVAL):
    try:
        print str(i)         


        

Answer 1

code flow is as follows:

1. for grabs new object from list (generated by range) and sets i to it
2. try
3. print
4. go back to 1

If you hit CTRL-C in the part 1 it is outside the try/except, so it won't catch the exception.

Try this instead:

MaxVal = 10000
StepInterval = 10

try:
    for i in range(1, MaxVal, StepInterval):
        print i
except KeyboardInterrupt:
    pass

print "done"

Answer 2

Sounds like the program is done by the time control-c has been hit, but your operating system hasn't finished showing you all the output. .

Answer 3

I was having this same problem and I just found out what was the solution:

You're running this code in an IDE like PyCharm. The IDE is taking ctrl+c (keyboardinterrupt) as copy. Try running your code in the terminal.

Answer 4

It works.

I'm using Ubuntu Linux, and you? Test it again using something like MaxVal = 10000000