How to replace text in text file using bat file script?

Question

So I want to create a script that takes 3 arguments: path to file, exact word to replace, and with what to replace it. How to create such thing?

Generally I want it

Answer 1

Use fnr utility its better than other famous utility since it can search and replace based on regular expressions. Also for the UI lovers you can configure options in UI and it can generate command line string which can then be used in your script. Very easy to use even as command line stirng.

Find it here http://findandreplace.codeplex.com/

Also it is single exe without any dependicies, so easy to use.

Example:

fnr --cl --dir "" --fileMask "hibernate.*" --useRegEx 
      --find "find_str_expression" --replace "replace_string"

Answer 2

A quick google search found this:

http://www.dostips.com/?t=Batch.FindAndReplace

Answer 3

I have written something like 2 batch scripts in my life, but here's how to take input from the command line:

script.bat filepath find replace
%1 = filepath, %2 = find, %3 = replace

To do replacement, do something like:

for /f "tokens=1,* delims=]" %%A in ('"type %1|find /n /v """') do (
set "line=%%B"
if defined line (
    call set "line=echo.%%line:%~2=%~3%%"
    for /f "delims=" %%X in ('"echo."%%line%%""') do %%~X
    ) ELSE echo.
)

(taken directly from the link posted by @russ, with the variable numbers changed.)

I think this should work for you.