Keep trailing zeroes in python

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借酒劲吻你
借酒劲吻你 2020-12-18 22:43

I am writing a class to represent money, and one issue I\'ve been running into is that \"1.50\" != str(1.50). str(1.50) equals 1.5, and alll of a sudden, POOF.

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  • 2020-12-18 23:35

    You can use the format method on strings to specify how many decimal places you want to represent:

    >>> "{:.2f}".format(1.5)
    '1.50'
    

    But even better would be to use the decimal module for representing money, since representation issues with binary floats can give you slightly off results if you're doing arithmetic. The documentation for that module mentions some of those issues specifically - one of the most interesting ones for money applications is:

    >>> 0.1+0.1+0.1-0.3
    5.551115123125783e-17
    >>> from decimal import Decimal
    >>> Decimal('.1') + Decimal('.1') + Decimal('.1') - Decimal('.3')
    Decimal('0.0')
    
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  • 2020-12-18 23:36
    x = 1.500000
    
    print '%.2f' % x
    print '{:.3f}'.format(x)
    

    result

    1.50
    1.500
    
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  • 2020-12-18 23:42

    The proposed solutions do not work when the magnitude of the number is not known in advance, which is common in scientific applications rather than in money-related ones. I give an alternative solution for those, like me, coming to this question looking for the scientific case.

    For example, if I want to print x = 1.500e-4 to three significant digits (common situation when dealing with measurements with a given uncertainty), the following command obviously does not give the correct result:

    x = 1.500e-4
    print(f"{x:.3f}")
    
    ----> 0.000
    

    Here I used the modern Python 3.6+ f-strings for the formatting.

    One may think of using the g format specifier, but this also does not give the desired result to three significant digits as the trailing zero is omitted:

    x = 1.500e-4
    print(f"{x:.3g}")
    
    ----> 0.00015
    

    The correct answer can be obtained using the g format specifier together with a rather obscure option, the hash character #, of the format-specification mini language, in the following way:

    x = 1.500e-4
    print(f"{x:#.3g}")
    
    ----> 0.000150
    

    This formatting also works unchanged in the simpler case of the original question:

    x = 1.500
    print(f"{x:#.3g}")
    
    ----> 1.50
    
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  • 2020-12-18 23:46

    When working with money, always represent money using the Decimal class.

    http://docs.python.org/2/library/decimal.html

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