Changing marker style in scatter plot according to third variable

Question

I am dealing with a multi-column dictionary. I want to plot two columns and subsequently change color and style of the markers according to a third and fourth column.

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Answer 1

Easiest solution for me was to use pandas and seaborn:

import pandas as pd   # '0.25.3'
import seaborn as sns # '0.9.0'

data = pd.DataFrame(
    dict(x=[1,2,3,4,5,6],
    y=[1,3,4,5,6,7],
    m=['k','l','l','k','j','l'],)
)

sns.scatterplot(data=data, x='x', y='y', style='m')

seaborn automatically chooses the marker style for you.

Answer 2

Adding to the answer of Viktor Kerkez and using a bit of Numpy you can do something like the following:

x = np.array([1,2,3,4,5,6])
y = np.array([1,3,4,5,6,7])
m = np.array(['o','+','+','o','x','+'])

unique_markers = set(m)  # or yo can use: np.unique(m)

for um in unique_markers:
    mask = m == um 
    # mask is now an array of booleans that can be used for indexing  
    plt.scatter(x[mask], y[mask], marker=um)

Answer 3

The problem is that marker can only be a single value and not a list of markers, as the color parmeter.

You can either do a grouping by marker value so you have the x and y lists that have the same marker and plot them:

xs = [[1, 2, 3], [4, 5, 6]]
ys = [[1, 2, 3], [4, 5, 6]]
m = ['o', 'x']
for i in range(len(xs)):
    plt.scatter(xs[i], ys[i], marker=m[i])
plt.show()

Or you can plot every single dot (which I would not recommend):

x=[1,2,3,4,5,6]
y=[1,3,4,5,6,7]
m=['k','l','l','k','j','l']

mapping = {'j' : 'o', 'k': 'x', 'l': '+'}

for i in range(len(x)):
    plt.scatter(x[i], y[i], marker=mapping[m[i]])
plt.show()