I\'m using PHP 5.2.6. I want to have a default value for an argument in a method, but it seems I\'m getting a bit too clever.
The class property blnOverwrite
you just can shorten it a little:
public function place( $path, $overwrite = NULL ) {
if(!is_null($overwrite))$this->blnOverwrite = $overwrite;
...
}
but thats nearly the same
You absolutely can do this. Best of both worlds: initialize your default property AND your method's default argument with a class constant.
class Object {
const DEFAULT_BLNOVERWRITE = TRUE;
protected $blnOverwrite = self::DEFAULT_BLNOVERWRITE;
public function place($path, $overwrite = self::DEFAULT_BLNOVERWRITE) {
var_dump($overwrite);
}
}
$Object = new Object();
$Object->place('/'); //bool(true)
Yes, you have to do it this way. You cannot use a member value for the default argument value.
From the PHP manual on Function arguments: (emphasis mine)
A function may define C++-style default values for scalar arguments. […] PHP also allows the use of arrays and the special type NULL as default values. […] The default value must be a constant expression, not (for example) a variable, a class member or a function call. […] Note that when using default arguments, any defaults should be on the right side of any non-default arguments; otherwise, things will not work as expected.
You must do it that way, afaik, or use a class constant since php 5.3 but of course its fixed and cant be changed later so i would definitely go with your own solution:
class foo{
const constant = 'bar';
public function place($path, $overwrite = self::constant ) {
die('bla' . $overwrite);
}
}
$bar = new foo();
$bar->place('baz');