MLE error in R: initial value in 'vmmin' is not finite

Question

Suppose I have 2 data.frame objects:

df1 <- data.frame(x = 1:100)
df1$y <- 20 + 0.3 * df1$x + rnorm(100)
df2 <- data.frame(x = 1:200000         


        

Answer 1

I had the same problem when minimizin a log-likelihood function. After some debugging I found that the problem was in my starting values. They caused one specific matrix to have a determinant = 0, which caused an error when a log was taken of it. Therefore, it could not find any "finite" value, but that was because the function returned an error to optim.

Bottomline: consider if your function is not returning an error when you run it using the starting values.

PS.: Marius Hofert is completely right. Never suppress warnings.

Answer 2

known bug in R, bugzilla ID 17703. Notoriously difficult to reproduce.

Answer 3

The value of R becomes zero at some point; it leads to a non-finite value of the function to be minimized and returns an error.

Using the argument log=TRUE handles better this issue, see function LL3 below. The following gives some warnings but a result is returned, with parameter estimates close to the true parameters.

require(stats4)
set.seed(123)
e <- rnorm(200000)
x <- 1:200000
df3 <- data.frame(x)
df3$y <- 20 + 0.3 * df3$x + e
LL3 <- function(a, b, mu, sigma) {
  -sum(dnorm(df3$y - a- b * df3$x, mu, sigma, log=TRUE))
}
mle3 <- mle(LL3, start = list(a = 20, b = 0.3,  sigma=0.5),
  fixed = list(mu = 0))
Warning messages:
1: In dnorm(df3$y - a - b * df3$x, mu, sigma, log = TRUE) : NaNs produced
2: In dnorm(df3$y - a - b * df3$x, mu, sigma, log = TRUE) : NaNs produced
3: In dnorm(df3$y - a - b * df3$x, mu, sigma, log = TRUE) : NaNs produced
4: In dnorm(df3$y - a - b * df3$x, mu, sigma, log = TRUE) : NaNs produced
5: In dnorm(df3$y - a - b * df3$x, mu, sigma, log = TRUE) : NaNs produced
6: In dnorm(df3$y - a - b * df3$x, mu, sigma, log = TRUE) : NaNs produced
7: In dnorm(df3$y - a - b * df3$x, mu, sigma, log = TRUE) : NaNs produced
8: In dnorm(df3$y - a - b * df3$x, mu, sigma, log = TRUE) : NaNs produced

> mle3
Call:
mle(minuslogl = LL3, start = list(a = 20, b = 0.3, sigma = 0.5), 
    fixed = list(mu = 0))

Coefficients:
        a         b        mu     sigma 
19.999166  0.300000  0.000000  1.001803