Why map(print, a_list) doesn't work?

Question

For a normal function, map works well:

def increment(n):
    return n+1
l = [1, 2, 3, 4, 5]
l = map(increment, l)
print l
>>> [2, 3, 4,         


        

Answer 1

Because print is not a function.

But you can make print-wrapper, of course:

>>> def p(x):
...   print x
... 
>>> l = [1, 2, 3, 4, 5]
>>> l = map(p, l)
1
2
3
4
5

Answer 2

A better way to map print in 2.x would be to do

from __future__ import print_function

Answer 3

As others have said, in Python 2.x print is a statement. If you really want to do this in Python 2.x you can use pprint:

from pprint import pprint
l = [1, 2, 3, 4, 5]
p = map(pprint, l)

Answer 4

In Python 2.x, print is a statement, not a function. If you try this in Python 3.x it will work.

In Python 2.x, you can say print(x) and it is not a syntax error, but it isn't actually a function call. Just as 1 + (3) is the same as 1 + 3, print(x) is the same as print x in Python 2.x.

In Python 2.x you can do this:

def prn(x):
    print x

Then you can do:

map(prn, lst)

and it will work. Note that you probably don't want to do lst = map(prn, lst) because prn() returns None, so you will replace your list of values with a same-length list of just the value None.

EDIT: Two other solutions for Python 2.x.

If you want to completely change the behavior of print, you can do this:

from __future__ import print_function

map(print, lst)

This makes print into a function just as it is in Python 3.x, so it works with map().

Or, you can do this:

from pprint import pprint

map(pprint, lst)

pprint() is a function that prints things and it is available as a built-in. I'm not exactly sure how it is different from the default print (it says it is a "pretty-print" function but I'm not sure how exactly that makes it different).

Also, according to the PEP 8 standard, it is non-recommended to use l as a variable name, so I am using lst instead in my examples.

http://www.python.org/dev/peps/pep-0008/

Answer 5

From your line print l, I assume this is python2, where print is not a function, it's a statement.

Answer 6

The above answers work for Python 2, but not in Python 3 with the changes to both map and the print function.

The solution I've arrived at to achieve what I wanted map(print, lst) to do in Python 3 is to unpack the list inside of the print call.

lst = [1, 2, 3]
print(*lst, sep='\n')

Output:

1
2
3

You can find more detail around this in my answer to Use print inside lambda.