AM/PM to TimeSpan

Question

I want to achieve the converse of this, that is, I want to convert a string with format hh:mm tt to a TimeSpan with zeroed seconds.

Answer 1

The simplest approach would probably be to parse it as a DateTime using DateTime.ParseExact, and then use the TimeOfDay to exact the TimeSpan.

DateTime dateTime = DateTime.ParseExact(text,
                                    "hh:mm tt", CultureInfo.InvariantCulture);
TimeSpan span = dateTime.TimeOfDay;

It's odd to see a leading 0 on a number of hours when you're also specifying an am/pm designator though. You might want "h" instead of "hh" in the format string, to allow "9:45 pm" instead of "09:45 pm".

(I'd also argue that it's a strange use of TimeSpan in the first place, but then the .NET date/time types are somewhat messed up in my view. I'd recommend using Noda Time, but I'm biased :)

Answer 2

You can convert meridiem time to timespan and also timespan to meridiem time with date and only time using below code snipet...

        TimeSpan ts = DateTime.Parse("8:00 PM").TimeOfDay;                        
        DateTime dateWithTimeSlot = DateTime.Today+ ts;              

        //for getting MM/dd/yyyy hh:mm tt format
        string dateWithMeridiemTimeSlot =  
            dateWithTimeSlot.ToString("MM/dd/yyyy hh:mm tt: ", CultureInfo.InvariantCulture);

        Console.WriteLine("For getting MM/dd/yyyy hh:mm tt format: "+dateWithMeridiemTimeSlot);

        //for getting only hh:mm tt format
        string meridiemTimeSlot =
            dateWithTimeSlot.ToString("hh:mm tt", CultureInfo.InvariantCulture);

        Console.WriteLine("For getting only hh:mm tt format: " + meridiemTimeSlot);

        Console.ReadLine();

Let's enjoy!

Thanks

Answer 3

TimeSpan tspan;

tspan = DateTime.ParseExact("01:45 PM", "hh:mm tt", CultureInfo.InvariantCulture).TimeOfDay;

Answer 4

This work for Me.

TimeSpan ts= DateTime.Parse("8:00 PM").TimeOfDay;