How can I get a char array in reverse order?

Question

my assignment question is like that

Write a program which prints the letters in a char array in reverse order using

void printReverse(char         


        

Answer 1

I believe what you wrote is the signature of the method you have to create.

public void printReverse(char[] letters, int size){
   //code here
}

You would have to iterate the array and print what it contains backwards. Use a reverse "for loop" to go through each item in "letters". I'll let you combine these yourself as it's an assignment. Here's an example of a for loop:

for (int i = array.length-1; i >= 0 ; i--){
    System.out.print(array[i]);
}

Answer 2

`

//not only prints the reverse order, but creates new char array with chars in desired order
char[] letters = {'e', 'v', 'o', 'l', '4'};
int i = letters.length - 1, j = 0;
char[] let = new char[letters.length];
while(i >= 0){
     let[j] = letters[i];
     i--;
     j++;
}
for (char c : let){
     System.out.print(c);
}

`

output: 4love

Answer 3

void printReverse(char letters[], int size) is the signature of the function that you have to do. E.g.

void printReverse(char letters[], int size) {
//your code goes here
}

and call it from your main window with the parameters.

Answer 4

#include<stdio.h>
int main()
  {
int i;
int temp;
int end;
int n=6;
int ar[6]={1, 2,3 , 4, 5, 6};
end=n-1;
printf("%d\n",end );
for(i = 0; i < 6; ++i)
 {
    temp=ar[i];
    ar[i]=ar[end];
    ar[end]=temp;
    end--;
    if(sizeof ar[6]/2==end){
        break;
    }
 } 
 printf("\n");
 for (int i = 0; i < 6; ++i)
 {
    printf("%d",ar[i] );
 }
 return 0;
}

/one can write same for any type of array/

Answer 5

import java.util.Scanner;

public class StringReverse {

    static String input;
    void completeReverse(){
        char[] ch = StringReverse.input.toCharArray();
        for(int i =ch.length-1;i>=0;i--){
            System.out.print(ch[i]);
        }
    }
    void partialReverse(){
        String charOfSplit =" ";
        // splitting and creating array on space character.
        String[] split =StringReverse.input.split(charOfSplit);
        //using loop on each index of split characters.
        for(int i=0; i<split.length;i++){
           // System.out.println(split[i]);
            //breaking individual index in char array with different index value.
            char[] indexedValue = split[i].toCharArray();
            for(int j=indexedValue.length-1;j>=0;j--){
                //printing that char array reverse order
                System.out.print(indexedValue[j]);
            }
            // giving spaces for another index value after space given by user.
            System.out.print("  ");
        }
    }

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        StringReverse sr =new StringReverse();
        System.out.print("Enter the String: ");
        //trimming every space before and after the string.
        StringReverse.input = sc.nextLine().trim();
        System.out.print("Complete Reverse: ");
        sr.completeReverse();
        System.out.println();
        System.out.print("Partial Reverse: ");
        sr.partialReverse();
    }
}

Answer 6

Man you code is right except some minor changes in the main method and in the loop and the method has to be static.

The signature printReverse(char[] letters, int size) means that when you call it, you have to pass char array and the size of the array

Try the following

import java.util.Arrays;
import java.util.Collections;

public class search {

    public static void main(String[] args) {          

   char[] letters = {'e', 'v', 'o', 'l', '4'};

   printReverse(letters,5);

}

public static void printReverse(char[] letters, int size){

    for (int i = size-1; i >= 0 ; i--)
    {

     System.out.print(letters[i]);
    }
  }

 }