How to update a mysql database without reloading page

Question

thanks for looking. I have a very long list of items, users click on an image (a plus sign) to add the item to their personal list. At the moment when they click the + it l

Answer 1

http://jquery.com/ would be my suggestions. You are going to need to do some AJAX calls to the server to have it interact with your DB and then get a result back and display that information to the user. I prefer JQuery as it simplifies a lot of these calls and the documentation for it is fairly good. There are tons of tutorials around for the basics.

A simple google search reveals quite a few http://www.google.com/search?q=jquery+ajax+tutorial

Answer 2

You need AJAX, as everyone has said.

Since you have never written any javascript, here is a guide for you.

Instead of your

<a href="add-item.php?itemid='.$itemId.'" > Add Item </a>

Write

<a onclick="addItemToUsersList('.$itemId.')" > Add </a>

For AJAX, use jquery as Angelo has suggested. Download it and add the following

<script type="text/javascript" src="http://path/to/jquery-latest.min.js"></script>
<script type="text/javasript">
function addItemToUsersList(itemId)
{
  $.ajax({
    'url': 'path/to/add-item.php', 
    'type': 'GET',
    'dataType': 'json', 
    'data': {itemid: itemId}, 
    'success': function(data) 
    {
      if(data.status)
      {
        if(data.added)
        {
          $("span#success"+itemId).attr("innerHTML","Item added to your personal list");
        }
        else
        {
          $("span#success"+itemId).attr("innerHTML","This item is already on your list");
        }
      }
    },
    'beforeSend': function() 
    {
      $("span#success"+itemId).attr("innerHTML","Adding item to your bucketlist...");
    },
    'error': function(data) 
    {
      // this is what happens if the request fails.
      $("span#success"+itemId).attr("innerHTML","An error occureed");
    }
  });
}
</script>

And then finally, in your path/to/add-item.php file write the code to add the items. The parameter itemId will be available here as $_GET['itemId']. Just return proper status values using json_encode.

if($bucketlist < 1) 
{
  mysql_query("INSERT INTO membersbuckets (memberbucketid, userid, bucketid, complete) VALUES ('', '$userid', '$_GET['itemId]', '0')");
  return json_encode(array("status" => true, "added" => true));
}
else
{
  return json_encode(array("status" => true, "added" => false));
}

Answer 3

You would achieve this via JavaScript utilizing something referred to as "AJAX". An Asynchronous JavaScript And XML request allows JavaScript to send a request to another page and get the results from it.

So utilizing ajax, you would go to the URL you wanted, and then you could display the message to a user.

I use a library called jQuery to get something like this done

$.ajax({
    'url': 'path/to/add-item.php', 
    'type': 'GET',
    'dataType': 'json', 
    'data': {itemid: xx}, 
    'success': function(data) {
      // what happens if the request was completed properly
    },
    'error': function(data) {
      // what happens if the request fails.
    }
  });

Note that just because a request completes properly, doesn't mean the item was added as necessary.

I would suggest you read up on the following to get a good understanding of how exactly to adapt this to your needs.

http://json.org/

http://api.jquery.com/jQuery.ajax/

http://ca3.php.net/json_encode

Answer 4

You may really want to use Javascript in your project! See, because you are telling that you dont want to navigate out of the current page and want to give a small message on the current page saying a confirmation to the user.. then u need to use something called as AJAX-Asynchronous Javascript and XML. Its a addition of PHP and Javascript.

Using AJAX u can update currently loaded page without refreshing it. Here HTML is not connecting or requesting the server but its the Javascript. Hence u can achieve -> [how would I go about making it all update the database without going anywhere]..

And as far AJAX and Javascript is concerned, they r very simple! Just need to learn basic syntax of them and den on u can go further!!!

references u can refer to:

-> Best book for u to refer is -

Professional Ajax Nicholas C. Zakas, Jeremy McPeak, Joe Fawcett