The model item passed into the dictionary is of type 'System.Data.Entity.Infrastructure.DbQuery', but this dictionary requires a model item of type B

Question

I been stuck in a situation and I tried finding the solution for it on net but was not successful. I am new to MVC with Entity Framework, and it is throwing the exception wh

Answer 1

None of the answers worked for me, but in the end, for some reason, EF 6 seemed to interpret this as a query:

var patient = db.Patient.Where(p => p.ID == id);

while this returned the Model I needed and works for me:

var patient = db.Patient.Where(p => p.ID == id).FirstOrDefault();

Answer 2

As Shad points out, the reason you are getting this error is simply because you are passing a different type of data into the view than what you have said you would.

To solve this, you need a model that you can pass into your view that holds the data you need:

public class FooBarModel
{
    public AbortReason Foo { get;set;}
    public Activity Bar { get;set;}
}

Then, in your Index method, do something like this:

using(MobilePhoneXchangeEntities1 ent = new MobilePhoneXchangeEntities1())
{
    var result = from foo in ent.t_AbortReason
                 from bar in ent.t_Activity
                 where foo.AbortReasonCategoryId != null && bar.ActivityId != null
                 select new FooBarModel() { Foo = foo, Bar = bar };
    return View(result);
}

And in your view, set the model type:

@model IEnumerable<my.namespace.FooBarModel>

Answer 3

The model item passed into the dictionary is of type 'Person.Models.Location', but this dictionary requires a model item of type 'Person.Models.LoginModel'.

Answer 4

Your view expects model of type UnRelatedEntity.Models.MobilePhoneXchangeEntities1, but you pass result object to it. result is a database query, which you have described in controller action. So, you get expected error - type mismatch.

To fix this you should create type for your query items. Very simple example:

public class ResultItem
{
    public Foo Foo { get; set; }
    public Bar Bar { get; set; }
}

After that modify select statement in your query:

select new ResultItem { Foo = foo, Bar = bar };

and in the end, change model type of the view to IEnumerable<ResultItem>, because query will return collection of result items.

Answer 5

Add a new object or instance with the correct type

@Html.Partial("_LoginPartial", new MVCTest.Models.LoginViewModel())