Passing associative array as argument with Bash [duplicate]

Answer 1

It's ugly enough using variable indirection with regular arrays, working with associative arrays is difficult -- I did not find a way to iterate over the keys.

I wonder if all you need is declare -p:

print_array() { declare -p $1; }
print_array weapons

declare -A weapons='(["Imperial Sword"]="90" ["Tainted Dagger"]="54" ["Edged Shuriken"]="25" ["Straight Sword"]="75" )'

Or, prettier:

print_array() { declare -p $1 | sed 's/[[)]/\n&/g'; }
print_array weapons

declare -A weapons='(
["Imperial Sword"]="90" 
["Tainted Dagger"]="54" 
["Edged Shuriken"]="25" 
["Straight Sword"]="75" 
)'

Answer 2

#!/bin/bash

   declare -A dict
   
   dict=(
    [ke]="va"
    [ys]="lu"
    [ye]="es" 
   ) 
   
   fun() {
     for i in $@; do
       echo $i
     done
    }
   
   fun ${dict[@]} 

# ||${dict[key]} || ${!dict[@]} || ${dict[$1]} || ${dict[@]}

Answer 3

you can use local -n for a reference

 declare -A weapons=(
 ['Straight Sword']=75
 ['Tainted Dagger']=54
 ['Imperial Sword']=90
 ['Edged Shuriken']=25
 )

 print_weapons() {
     local -n array=$1
     for i in "${!array[@]}"; do
         printf "%s\t%d\n" "$i" "${array[i]}"
     done
 }

 print_weapons weapons

Answer 4

I don't think you can pass associative arrays as an argument to a function. You can use the following hack to get around the problem though:

#!/bin/bash

declare -A weapons=(
  ['Straight Sword']=75
  ['Tainted Dagger']=54
  ['Imperial Sword']=90
  ['Edged Shuriken']=25
)

function print_array {
    eval "declare -A arg_array="${1#*=}
    for i in "${!arg_array[@]}"; do
       printf "%s\t%s\n" "$i ==> ${arg_array[$i]}"
    done
}

print_array "$(declare -p weapons)" 

Output

Imperial Sword ==> 90   
Tainted Dagger ==> 54   
Edged Shuriken ==> 25   
Straight Sword ==> 75