Java: split() returns [Ljava.lang.String;@186d4c1], why?

Question

And i have no idea why!

I bascially have a STRING (yes, not an array), that has the following contents:

[something, something else, somoething, trall         


        

Answer 1

You are getting a valid array of Strings, but trying to print it directly does not do what you would expect it to do. Try e.g.

System.out.println(Arrays.asList(urlArr));

Update

If you want to process the parsed tokens one by one, you can simply iterate through the array, e.g.

for (String url : urlArr) {
  // Do something with the URL, e.g. print it separately
  System.out.println("Found URL " + url);
}

Answer 2

When you do toString on an Array, you just get the internal representation. Not that useful. Try Arrays.toString(what comes back from split) for something more readable.

Answer 3

The output

[Ljava.lang.String;@186d4c1

is the way java prints a string array (or any array) by default (when converted to a string). You may use

Arrays.toString(urlArr)

to get a more readable version.