Show a div only once per time the user is on the site

Question

I\'m trying to show a div element only once per time that the user is on the site. I\'ve seen multiple answers to similar questions already, but none of them seem to work...

Answer 1

You could use localStorage instead, only when the user clears it out he will get the popup again (same with cookies) but its much simplier:

(function() {
    var visited = localStorage.getItem('visited');
    if (!visited) {
        document.getElementById("popupp").style.visibility = "visible";
        localStorage.setItem('visited', true);
    }
})();

html:

<div id="popupp" style="visibility:hidden;">hi</div>

This way you get a lot of less code. Hope this helps.

Answer 2

If the goal is to only show it once, you can use the example on the MDN website as a start.

if (document.cookie.replace(/(?:(?:^|.*;\s*)someCookieName\s*\=\s*([^;]*).*$)|^.*$/, "$1") !== "true") {
  alert("Do something here!");
  document.cookie = "someCookieName=true; expires=Fri, 31 Dec 9999 23:59:59 GMT; path=/";
}

http://jsfiddle.net/daCrosby/pqb5baa5/

Edit

Here it is showing you div. Note, I moved the styling to CSS instead of inline in my jsFiddle - much better approach to get in the hang of

if (document.cookie.replace(/(?:(?:^|.*;\s*)someCookieName\s*\=\s*([^;]*).*$)|^.*$/, "$1") !== "true") {
    document.getElementById("popupp").style.visibility = "visbile";
    document.cookie = "someCookieName=true; expires=Fri, 31 Dec 9999 23:59:59 GMT; path=/";
}

http://jsfiddle.net/daCrosby/pqb5baa5/2/

Answer 3

Try this: in html: class="popupp" change to id="popupp"

and in javascript: document.getElementById("popupp").style.visibility = visible; change to document.getElementById("popupp").style.visibility = "visible";

Demo