I\'ve got a two-dimension string vector that I need to print out. The whole program should read a line from a txt file, store each word from it as a different element and th
I would change it to the following:
for (int i = 0; i < vec.size(); i++)
{
for (int j = 0; j < vec[i].size(); j++)
{
cout << vec[i][j];
}
}
If you have a vector of vectors then you can print it the following way using the range based for statement
std::vector<std::vector<std::string>> v;
//...
for ( const auto &row : v )
{
for ( const auto &s : row ) std::cout << s << ' ';
std::cout << std::endl;
}
If you need a solution based on C++ 2003 then the code could look like
for ( size_t i = 0; i < v.size(); i++ )
{
for ( size_t j = 0; j < v[i].size(); j++ ) std::cout << v[i][j] << ' ';
std::cout << std::endl;
}
You can easily loop through the vector by its size, just use the size()
member function:
for (int i = 0; i < vec.size(); i++)
{
for (int j = 0; j < vec[i].size(); j++)
{
cout << vec[i][j];
}
}
Use function size()
to get the number of elements.
std::vector< std::vector<std::string> > vec;
for (unsigned int i = 0; i < vec.size(); ++i)
{
for (unsigned int j = 0; j < vec[i].size(); ++j)
{
cout << vec[i][j];
}
cout << std::endl;
}