$result = mysql_query()

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I am brand new to php/mysql, so please excuse my level of knowledge here, and feel free to direct me in a better direction, if what I am doing is out of date.

I am p

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抹茶落季

2020-12-18 11:06
It is hard to help without knowing more. You are pumping the results into an array, are you expecting to only return one result or many banner_headline results? If you will only ever get one result then all you need to do is something like this:

PHP:
```
$result = mysql_query("
    SELECT `banner_headline`
    FROM `low_engagement`
    WHERE `thread_segment` = 'a3'", $connection) or die(mysql_error());
// This will get the zero index, meaning first result only
$alt = mysql_result($result,0,"banner_headline");
```
HTML:
```
<html>
<body>

<img src="" alt="<?php echo $alt ?>">
```
On a side note, you should stop using mysql-* functions, they are deprecated.
You should look into PDO or mysqli
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花落未央

2020-12-18 11:08

You are, as the comment says, using deprecated functions, but to answer your question, you should declare a variable to hold the value once your retrieve it from the database so that you can use it whenever your want.

<?php
$result = mysql_query("SELECT banner_headline FROM low_engagement WHERE thread_segment = 'a3'", $connection);
if(!$result) {
    die("Database query failed: " . mysql_error());
}

$bannerHeadline = "";

while ($row = mysql_fetch_array($result)) {
    $bannerHeadline = $row["banner_headline"];
}

echo $bannerHeadline; //use this wherever you want

?>

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