Java JSP/Servlet: controller servlet throwing the famous stack overflow

Question

I\'ve read several docs and I don\'t get it: I know I\'m doing something wrong but I don\'t understand what. I\'ve got a website that is entirely dynamically generated: the

Answer 1

Try using struts in which front controller pattern is inbuilt. There you will have a action class and you can define forwards in struts-config file using which you can easily manage the forwards.

Go through the tutorial http://www.roseindia.net/struts/struts2/index.shtml. Hope this helps you.

Answer 2

Unfortunately, Serlvet spec doesn't allow to create a servlet mapping to match only incoming request, not forwards. However, this can be done for filter mappings (and by default filter mappings match only incoming requests).

So, the typical solution for intercepting everything with a single servlet is to use a UrlRewriteFilter:

<filter>
    <filter-name>urlRewrite</filter-name>
    <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>
</filter>

<filter-mapping>
    <filter-name>urlRewrite</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<servlet>
    <servlet-name>application</servlet-name>
    <servlet-class>...</servlet-class>
</servlet>

<servlet-mapping>
    <servlet-name>application</servlet-name>
    <url-pattern>/app/*</url-pattern>
</servlet-mapping>

/WEB-INF/urlrewrite.xml:

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE urlrewrite
    PUBLIC "-//tuckey.org//DTD UrlRewrite 3.0//EN"
    "http://tuckey.org/res/dtds/urlrewrite3.0.dtd">

<urlrewrite default-match-type="wildcard">
    <rule>
        <from>/**</from>
        <to>/app/$1</to>
    </rule>
    <outbound-rule>
        <from>/app/**</from>
        <to>/$1</to>
    </outbound-rule>    
</urlrewrite>

This way also allows you to specify exceptions from /* mapping for static files.