I have a table with columns for ID
, firstname
, lastname
, address
, email
and so on.
Is there any way
DELETE FROM table WHERE id NOT IN (SELECT MIN(id) FROM table GROUP BY email)
This keeps the lowest, first inserted id's for every email.
While MiPnamic's answer is essentially correct, it doesn't solve the problem of which record you keep and which you throw away (and how you sort out related records). The short answer is that this cannot be done programmatically.
Given a query like this:
SELECT email, MAX(ID), MAX(firstname), MAX(lastname), MAX(address)
FROM customers
makes it even worse - since you are potentially selecting a mixture of fields from the duplicate rows. You'd need to do something like:
SELECT csr2.*
FROM customers csr2
WHERE ID IN (
SELECT MAX(id)
FROM customers csr
GROUP BY email
);
To get a unique set of existing rows. Of course you still need to sort out all the lreated records (hint - that's the IDs ni customers table not returned by the query above).
DELETE n1 FROM customers n1, customers n2 WHERE n1.ID > n2.ID AND n1.email = n2.email
I don't know if this will work in MYSQL (I haven't used it)... but you should be able to do something like the following snippets.
I'd suggest you run them in order to get a feel for if the right data is being selected. If it does work, then you probably want to create a constraint on the column.
Get all of the duplicate e-mail addresses:
SELECT
EMAILADDRESS, COUNT(1)
FROM
TABLE
GROUP BY EMAILADDRESS
HAVING COUNT(1) > 1
Then determine the ID from that gives:
SELECT
ID
FROM
TABLE
WHERE
EMAILADDRESS IN (
SELECT
EMAILADDRESS
FROM
TABLE
GROUP BY EMAILADDRESS
HAVING COUNT(1) > 1
)
Then finally, delete the rows, based on the above and other constraints:
DELETE
FROM
TABLE
WHERE
ID IN (
SELECT
ID
FROM
TABLE
WHERE
EMAILADDRESS IN (
SELECT
EMAILADDRESS
FROM
TABLE
GROUP BY EMAILADDRESS
HAVING COUNT(1) > 1
)
)
AND FIRSTNAME = 'Instant'