R:Binary matrix for all possible unique results

Question

How to generate a binary matrix for all possible permutations of \'i\' variables X, where \" i \" can be any number between 1 and infinite. Resultant matrix will have 2^ i u

Answer 1

The fonction combos of the package hier.part will do the job I think.

require(hier.part)
combos(2)$binary
     [,1] [,2]
[1,]    1    0
[2,]    0    1
[3,]    1    1

combos(3)$binary
     [,1] [,2] [,3]
[1,]    1    0    0
[2,]    0    1    0
[3,]    0    0    1
[4,]    1    1    0
[5,]    1    0    1
[6,]    0    1    1
[7,]    1    1    1

Except that you will have to add the "null" combination. HTH

Answer 2

you can use expand.grid:

 expand.grid(c(0,1),c(0,1))
  Var1 Var2
1    0    0
2    1    0
3    0    1
4    1    1

More generally, with 5 columns for example, giving m:

m <- as.data.frame(matrix(rbinom(5*2, 1, 0.5),ncol=5))
 V1 V2 V3 V4 V5
1  0  1  1  0  0
2  0  1  1  0  0

dim(expand.grid(m))
32 5

Answer 3

Try this

i =2
install.packages('gtools')
library(gtools)
permutations(2,i,v=c(0,1),repeats.allowed=TRUE)