Comparing similar xml files with XmlUnit with unordered tags (same tag name with different attributes)

Question

I am trying successfully XmlUnit, and is very helpful in my job. Now, I have a little problem, that I don\'t know how to solve. I have a java class, that has a Set, and when

Answer 1

Above solution only works with attributes order but it will not work if you have issues with the same element type order like below:

    <CustomerDataSet>
        <CustomerData>
            <Key>ACCOUNT_TYPE</Key>
            <Value>GREEN</Value>
        </CustomerData>
        <CustomerData name = "bla">
            <Key>EMAIL_ADDRESS</Key>
            <Value>MVNO_Automation_8@test.fr</Value>
        </CustomerData>
        <CustomerData>
            <Key>DATE_OF_BRITH</Key>
            <Value>01-01-1976</Value>
        </CustomerData>
    </CustomerDataSet>

            <CustomerDataSet>
        <CustomerData name = "bla">
            <Key>EMAIL_ADDRESS</Key>
            <Value>MVNO_Automation_8@test.fr</Value>
        </CustomerData>
        <CustomerData>
            <Key>ACCOUNT_TYPE</Key>
            <Value>GREEN</Value>
        </CustomerData>
        <CustomerData>
            <Key>DATE_OF_BRITH</Key>
            <Value>01-01-1976</Value>
        </CustomerData>
    </CustomerDataSet>

However, you can work around this by using RecursiveElementNameAndTextQualifier instead.

Answer 2

I found the solution by myself.

Diff diff = new Diff(controlXml, responseXml);
diff.overrideElementQualifier(new ElementNameAndAttributeQualifier());

Answer 3

This seems to work for XMLUnit 2.0:

    Diff myDiff = DiffBuilder.compare(Input.fromString(expected))
            .withTest(Input.fromString(actual))
            .withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byNameAndAllAttributes))
            .checkForSimilar()
            .build();