polygons from coordinates

前端 未结 1 1375
借酒劲吻你
借酒劲吻你 2020-12-18 04:35

I\'ve got a data.frame with lats and lngs that define the boundaries of rectangular boxes, like so

  geohash north_lat         


        
相关标签:
1条回答
  • 2020-12-18 05:27

    The key to creating polygons is that the coordinates have to be in sequence to form a closed area (i.e., the last point is the same as the first point).

    So your data will need a bit of manipulation to create the coordinates, and put them in order. In my example I've done this with an lapply

    Then the rest can be taken from the sf examples

    lst <- lapply(1:nrow(df), function(x){
      ## create a matrix of coordinates that also 'close' the polygon
      res <- matrix(c(df[x, 'north_lat'], df[x, 'west_lng'],
               df[x, 'north_lat'], df[x, 'east_lng'],
               df[x, 'south_lat'], df[x, 'east_lng'],
               df[x, 'south_lat'], df[x, 'west_lng'],
               df[x, 'north_lat'], df[x, 'west_lng'])  ## need to close the polygon
             , ncol =2, byrow = T
      )
      ## create polygon objects
      st_polygon(list(res))
    
    })
    
    ## st_sfc : creates simple features collection
    ## st_sf : creates simple feature object
    sfdf <- st_sf(geohash = df[, 'geohash'], st_sfc(lst))
    
    sfdf
    # Simple feature collection with 2 features and 1 field
    # geometry type:  POLYGON
    # dimension:      XY
    # bbox:           xmin: 48.64746 ymin: -4.350586 xmax: 48.69141 ymax: -4.262695
    # epsg (SRID):    NA
    # proj4string:    NA
    # geohash                    st_sfc.lst.
    # 1   gbsuv POLYGON((48.69141 -4.350586...
    # 2   gbsuy POLYGON((48.69141 -4.306641...
    
    plot(sfdf)
    

    0 讨论(0)
提交回复
热议问题