I am using Jersey to make some of my services RESTful.
My REST service call returns me
{\"param1\":\"value1\", \"param2\":\"value2\
To return the entries in array-type style, you should build your entity from array. Try the following:
@GET
@Produces({MediaType.APPLICATION_JSON, MediaType.APPLICATION_JSON})
public Response getSomeList() {
List<com.abc.def.rest.model.SimplePojo> yourListInstance =
new List<com.abc.def.rest.model.SimplePojo>();
/*
Do something
*/
return Response.ok(yourListInstance.toArray()).build();
}
if you face some trouble according to return type of toArray()
method - you could explicitly cast your array:
Response
.ok((com.abc.def.rest.model.SimplePojo[])yourListInstance.toArray())
.build();
UPD: try to convert your list to JSONArray:
JSONArray arr = new JSONArray();
for (SimplePojo p : yourListInstance) {
arr.add(p);
}
and then:
Response.ok(arr).build();
You can define your service method as follows, using Person POJO:
@GET
@Produces("application/json")
@Path("/list")
public String getList(){
List<Person> persons = new ArrayList<>();
persons.add(new Person("1", "2"));
persons.add(new Person("3", "4"));
persons.add(new Person("5", "6"));
// takes advantage to toString() implementation to format as [a, b, c]
return persons.toString();
}
The POJO class:
@XmlRootElement
public class Person {
@XmlElement(name="fn")
String fn;
@XmlElement(name="ln")
String ln;
public Person(){
}
public Person(String fn, String ln) {
this.fn = fn;
this.ln = ln;
}
@Override
public String toString(){
try {
// takes advantage of toString() implementation to format {"a":"b"}
return new JSONObject().put("fn", fn).put("ln", ln).toString();
} catch (JSONException e) {
return null;
}
}
}
The results will look like:
[{"fn":"1","ln":"2"}, {"fn":"3","ln":"4"}, {"fn":"5","ln":"6"}]