distinct() with pagination() in laravel 5.2 not working

Question

I\'m trying to use distinct() with pagination() in laravel 5.2 with fluent and it\'s given result proper but pagination remain same(Like w

Answer 1

The distinct is working.... When you make a join, it checks for distinct entries in all selected columns and here.. the column names you get after the join are also included in the join...

To run this please add select() to your builder instance and it should work :)

DB::table('myTable1 AS T1')
  ->join('myTable2 AS T2','T2.T1_id','=','T1.id')
  ->select('T1.*')
  ->distinct()
  ->paginate(5);

Let me know if this doesn't work for you :)

Answer 2

Use groupBy() instead of distinct(). I haven't tested but it will work. I was facing same issue in my query.

$author = Author::select('author_name')->groupBy('author_name')->paginate(15); 

Answer 3

If it is possible, you can change distinct() with groupBy().

Answer 4

There seems to be some ongoing issues with Laravel and using distinct with pagination.

In this case, when pagination is determining the total number of records, it is ignoring the fields you have specified in your select() clause. Since it ignores your columns, the distinct functionality is ignored as well. So, the count query becomes select count(*) as aggregate from ...

To resolve the issue, you need to tell the paginate function about your columns. Pass your array of columns to select as the second parameter, and it will take them into account for the total count. So, if you do:

/*DB::stuff*/->paginate(5, ['T1.*']);

This will run the count query of:

select count(distinct T1.*) as aggregate from

So, your query should look like:

DB::table('myTable1 AS T1')
    ->select('T1.*')
    ->join('myTable2 AS T2','T2.T1_id','=','T1.id')
    ->distinct()
    ->paginate(5, ['T1.*']);

Answer 5

I found the problem at my code, that is I need to pass $column as second parameter into paginate($perPage, $columns, $pageName, $page). I got the solution from laravel git issue.

So my working code:

DB::table('myTable1 AS T1')
->select('T1.*')
->join('myTable2 AS T2','T2.T1_id','=','T1.id')
->distinct()
->paginate(5, ['T1.*']);

Need suggestion
What if, I hack the code for Builder.php to bypass passing the second parameter $column. I mean this is the good thing OR any batter option?

/**
 * Paginate the given query into a simple paginator.
 *
 * @param  int  $perPage
 * @param  array  $columns
 * @param  string  $pageName
 * @param  int|null  $page
 * @return \Illuminate\Contracts\Pagination\LengthAwarePaginator
 */
public function paginate($perPage = 15, $columns = null, $pageName = 'page', $page = null)
{

    //To solved paginator issue with distinct...
    if(is_null($columns) && strpos($this->toSql(), 'distinct') !== FALSE){
        $columns = $this->columns; 
        $columns = array_filter($columns, function($value) {
            return (is_string($value) && !empty($value));
        });
    }
    else {
        //If null $column, set with default one
        if(is_null($columns)){
            $columns = ['*'];
        }
    }

    $page = $page ?: Paginator::resolveCurrentPage($pageName);

    $total = $this->getCountForPagination($columns);

    $results = $total ? $this->forPage($page, $perPage)->get($columns) : [];

    return new LengthAwarePaginator($results, $total, $perPage, $page, [
        'path' => Paginator::resolveCurrentPath(),
        'pageName' => $pageName,
    ]);
}