stealing bits from a pointer

Question

In The Art of Multiprocessor Programming, p215, the authors say that in C, you could \"steal\" a bit from a pointer, and using bit-wise operators extract some flag (a mark)

Answer 1

1. Make sure the pointee objects are aligned in memory so that all your pointers are even numbers. The last bit is then free for storing a single boolean flag. (This cannot be done completely portably. so you need knowledge of the platform.)

2. Move the pointers around as integers of type uintptr_t. These can easily be manipulated:

   bool get_flag(uintptr_t p)
   {
       return p & 1;
   }
   
   void *get_pointer(uintptr_t p)
   {
       return (void *)(p & (UINTPTR_MAX ^ 1));
   }
   
   uintptr_t set_flag(uintptr_t p, bool value)
   {
       return (p & (UINTPTR_MAX ^ 1)) | value;
   }
   

Answer 2

Imagine a system with a 32-bit pointer size, but only 1GB of memory is available. You need only 30 bits to address the entire memory space, so the upper 2 bits are unused. You can use these upper two bits for your own purposes - for example, to mark pointers by pointer type (stack/global vs. dynamic).

Note that the code that you get as the result is about as non-portable as it gets. You need to be intimately familiar with the CPU on which your code runs - specifically, you need to know if the upper bits get dropped when an address from the pointer is sent to the address bus.