JavaScript concat string with backspace

Question

I have a function f similar to

function f(str){
    alert(\"abc\"+str);
}

Now, I want to use JavaScript special charecter \"\\b\" in such a

Answer 1

Interesting question. I first checked some assumptions about \b in JS.

If you try this:

console.log('abc\b\byz');

You get the same answer of 'abcyz'.

This means, it is not a function of concatentation, but a fundamental error in the approach.

I would modify your approach to use SubString, then to take the index of \b and slice out the previous character.

Answer 2

EDIT: I realized this may not be what the OP was looking for, but it is definitely the easier way to remove characters from the end of a string in most cases.

You should probably just use string.substring or string.substr, both of which return some portion of string. You can get the substring from 0 to the string's length minus 2, then concatenate that with "yz" or whatever.

Answer 3

Something like this:

function f(str, abc){
   if(!abc) abc = "abc";
   if (str.indexOf("\b") != "undefined")
   {
       abc = abc.slice(0,-1);
       str = str.replace("\b","");
       f(str, abc);
   }
   else alert(abc+str);
}

and as an added bonus you get to use recursion!

note that this is a little slower than doing it this way:

function f(str){
    var count = 0;
    var abc = "abc";
    for(var i = 0; i < str.length; i++)
    { 
       if(str[i] = "\b") //at least i think its treated as one character...
       count++;
    }
    abc = abc.slice(0, count * -1);
    alert(abc+str);
}

Answer 4

The problem comes from the fact that \b is just another character in the ASCII code. The special behaviour is only when implemented by some string reader, for example, a text terminal.

You will need to implement the backspace behaviour yourself.

function RemoveBackspaces(str)
{
    while (str.indexOf("\b") != -1)
    {
        str = str.replace(/.?\x08/, ""); // 0x08 is the ASCII code for \b
    }
    return str;
}

Example: http://jsfiddle.net/kendfrey/sELDv/

Use it like this:

var str = RemoveBackspaces(f("\b\byz")); // returns "ayz"