Simple Question: How to split date (08-17-2011) into month, day, year? PHP

Question

I have a variable called $orderdate and it is set to a date format like this mm-dd-yyyy.

In PHP how would I split this variable into $month, $day, $year?

Tha

Answer 1

A good approach is to use date_parse_from_format().

For your example:

$dateStr = '03-27-2015';
$dateArray = date_parse_from_format('m-d-Y', $dateStr);

This gives $dateArray as:

Array
(
    [year] => 2015
    [month] => 3
    [day] => 27
    [hour] => 
    [minute] => 
    [second] => 
...
)

Answer 2

If you are not certain about the input format you can also do the following:

$time  = strtotime($input);
$day   = date('d',$time);
$month = date('m',$time);
$year  = date('Y',$time);

Answer 3

list($month, $day, $year) =explode("-",$orderdate);

Answer 4

Use explode to split string

list($m,$d,$y)=explode('-',$date);

Answer 5

If you're sure about the format of input value, then:

$orderdate = explode('-', $orderdate);
$month = $orderdate[0];
$day   = $orderdate[1];
$year  = $orderdate[2];

You could also use preg_match():

if (preg_match('#^(\d{2})-(\d{2})-(\d{4})$#', $orderdate, $matches)) {
    $month = $matches[1];
    $day   = $matches[2];
    $year  = $matches[3];
} else {
    echo 'invalid format';
}

Additionally, you can use checkdate() to validate the date.