Check if list contains only item x

Question

Say all of w, x, y, and z can be in list A. Is there a shortcut for checking that it contains only x--eg. without negating the other variables?

w, x, y, and z

Answer 1

This checks that all elements in A are equal to x without reference to any other variables:

all(element==x for element in A)

Answer 2

A=[w,y,x,z]
all(p == x for p in A)

Answer 3

I'm not sure what without negating the other variables means, but I suspect that this is what you want:

if all(item == x for item in myList): 
    #do stuff

Answer 4

{x} == {w,x,y,z} & set(A)

This will work if all of [w,x,y,z] and items in A are hashable.

Answer 5

That, or if you don't want to deal with a loop:

>>> a = [w,x,y,z]
>>> a.count(x) == len(a) and a

(and a is added to check against empty list)

Answer 6

If all items in the list are hashable:

set(A) == set([x])