I am looking to use json_search to get the array path that corresponds to a value.
I have tried and this works:
SET @j = \'[\"3\", \"2\", \"1\"]\
This seems to work:
SET @j = '[3, 2, 1]';
SELECT JSON_CONTAINS(@j, '3', '$');
I have tried a workaround method, which is to CONCAT the string and cast it back to JSON and update the table. It's not the most elegant way, so if you guys have any suggestion, please let me know! :)
BEGIN
DECLARE var1 INT default -2; //offsets
DECLARE var2 INT default 2; //offsets
SELECT StatusID into @statusList FROM UserStatusesIndex;
SET @statusID_to_remove = OLD.StatusID;
SET @startIndex = INSTR(@statusList, @statusID_to_remove);
SET @charLength = CHAR_LENGTH(@statusID_to_remove);
IF @startIndex <= 2 THEN SET var1=-1, var2=2; //If its the first index
ELSEIF (CHAR_LENGTH(@statusList) - @startIndex <= 2) THEN SET var1=-3, var2=0; //If its the last index
ELSE SET var1=-2, var2=2;
END IF;
SET @newJson=CAST(CONCAT(SUBSTRING(@statusList, 1, @startIndex+var1), SUBSTR(@statusList, @startIndex + @charLength+var2, CHAR_LENGTH(@statusList) - @startIndex - @charLength+2)) as JSON);
UPDATE UserStatusesIndex SET StatusID=@newJson WHERE StatusCreator=OLD.StatusCreator;
END
Thanks!
It is by design, although I can not agree with mySQL team. This should be implemented.
https://bugs.mysql.com/bug.php?id=79233 [closed]
The specification at https://dev.mysql.com/worklog/task/?id=7909 says: "This function returns path(s) to the given string. The returned path(s) identify object members or array slots which are character strings."
So it seems that the intention of this function was to search for strings. The documentation should be updated to clarify that the function is for searching for string scalars, not for scalars in general.