Error (ORA-00923: FROM keyword not found where expected)

Question

    select 
      country_olympic_name, 
      SUM(part_gold) as \'Number of Gold Medals\'
    From
      games.country,
      games.participation
   where
      par         


        

Answer 1

Identifiers need to be quoted with double quotes ("). Single quotes (') denote a character value (not a "name").

Therefor you need to use:

SUM(part_gold) as "Number of Gold Medals"

More details in the manual:

• Database Object Names and Qualifiers
• Text literals

Answer 2

In my case, I had this query

SELECT BANK_NAME
DECODE (SWIFT_CODE, 'BRDEROBU', 'BRD',
                   'NO RESULT') RESULT
FROM BANK_GAR;

As you may see, I didn't had the semicolon after the SELECT BANK_NAME line.

The correct query is:

SELECT BANK_NAME,
DECODE (SWIFT_CODE, 'BRDEROBU', 'BRD',
                   'NO RESULT') RESULT
FROM BANK_GAR;

Answer 3

Check reserved words. This was my issue. For whatever reason using "size" as a column alias caused oracle to spit that exact error out and it had me scratching my head for a while.

select 1 size, 1 id from dual

Answer 4

You may try doing this:-

select 
  country_olympic_name, 
  SUM(part_gold) as "Number of Gold Medals"
From
  games.country,
  games.participation
where
  participation.country_isocode = country.country_isocode
group by
  country_olympic_name;

Answer 5

Try this...

SELECT
      COUNTRY_OLYMPIC_NAME,
      SUM ( PART_GOLD ) AS NUMBER_OF_GOLD_MEDALS
FROM
      GAMES.COUNTRY,
      GAMES.PARTICIPATION
WHERE
      PARTICIPATION.COUNTRY_ISOCODE = COUNTRY.COUNTRY_ISOCODE
GROUP BY
      COUNTRY_OLYMPIC_NAME;