Is there a more elegant way to add nullable ints?

Question

I need to add numerous variables of type nullable int. I used the null coalescing operator to get it down to one variable per line, but I have a feeling there is a more conc

Answer 1

List<Nullable<int>> numbers = new List<Nullable<int>>();
numbers.Add(sum1);
numbers.Add(sum2);
numbers.Add(sum3);

int total = 0;
numbers.ForEach(n => total += n ?? 0);

this way you can have as many values as you want.

Answer 2

How about just substituting (sumX ?? 0) for sumX in the corresponding non-nullable expression?

using System; 

namespace TestNullInts 
{ 
    class Program 
    { 
        static void Main(string[] args) 
        { 
            int? sum1 = 1; 
            int? sum2 = null; 
            int? sum3 = 3; 

            int total = 0; 
            total += (sum1 ?? 0) + (sum2 ?? 0) + (sum3 ?? 0); 

            Console.WriteLine(total); 
            Console.ReadLine(); 
        } 
    } 
} 

Answer 3

Just to answer the question most directly:

int total = (sum1 ?? 0) + (sum2 ?? 0) + (sum3 ?? 0);

This way the statements are "chained" together as asked using a +